The probability of rain on each of the five days is 1/6, except on the first day , when it is 2/5,and on the last day when it is 4/5.what is the probability that rain will occur on at ieast one of the five days?
a. 1/675
b. 5/72
c. 5/27
d. 22/27
e. 67/72
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6 comments:
1-p(No Rain)
so,
=1-(1-2/5))*(1-5/6)*(1-5/6)*(1-5/6)*(1-4/5).
=1-5/72
=67/72
Correct me if it is not correct.
ans is 67/72
ANS=1-((1-2/5)*(1-1/6)*(1-1/6)*(1/1/6)*(1-4/5))
=1-(3/5)*(5/6)*(5/6)*(5/6)*(1/5)
=1-5/72
=67/72
When the question says that "probability of rain on each day is 1/6" does it not mean that the probability is for it raining all the days? They have given separate probabilities for the 1st and 5th day. How can it have two probabilities? But if your interpretation of the problem is correct dont you think that the question is highly ambiguous?
67/72
67/72
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