Sunday, November 18, 2007

GRE ALGEBRA QUESTION OF THE DAY

Which of the following is equal to [1/(√3-√2)]2?

A. 1
B. 5
C. √6
D. 5 - √6
E. 5 + 2√6

6 comments:

Unknown said...

ans is 5+2sqrt6

Unknown said...

1/(SQRT3-SQRT2)^2
=1/(3+2-2SQRT6)
=1/(5-2SQRT6)
NOW MUL AND DIVIDE WITH 5+2SQRT6
WHICH IS
(5+2SQRT6)/(5SQR-4(6))
=(5+2SQRT6)/(25-24)
=5+2SQRT6

lahari said...

ans is e

Cool said...

Ans is E

Anonymous said...

just multiply top and bottom by (√3+√2) first, then bottom is simplified to (√3+√2)(√3-√2)=1. for the numerator, the square of (√3+√2) is easily solved to give 5+2√6, answer E.

Anonymous said...

ans is E