Monday, November 19, 2007

GRE MATH PROBLEM OF THE DAY

A photographer will arrange 6 people of 6 different heights for photograph by placing them in two rows of three so that each person in the first row is standing in front of someone in the second row) The heights of the people within each row must increase from left to right, and each person in the second row must be taller than the person standing in front of him or her) How many such arrangements of the 6 people are possible?
A) 5
B) 6
C) 9
D) 24
E) 36

9 comments:

Unknown said...

A
5 WAYS

shivani said...

A

Cool said...

I think 6 ways........

Unknown said...

its A 5ways.

Unknown said...

6 ways

NoBody said...

a=1, b=2, c=3, d=4, e=5 f=6

1)
4 5 6 -> row 2
1 2 3 -> row 1

2)
3 5 6
1 2 4

3)
3 4 6
1 2 5

4)
2 5 6
1 3 4

5)
2 4 6
1 3 5

The Answer is 5 ways...
PS:
If there's any other way of arrangin plz post....

Anonymous said...

it may be done in 9 ways..........

23456
1

3459
12

456
123

56
1234


6
12345



6
12345



6
12345


6
12345

6
12345

FreeIdea said...

ms subhadeep read ur questions properly
its 5 ways
and the ways are demonstrated by mr paul

Anonymous said...

i think 6 different ways logically