Two beads are to be independently and randomly
selected, one from each of tw o bags. If
2/7 of the beads in one bag and
3/7 of the beads in the other
bag are yellow, what is the probability that both
beads selected will be yellow?
(A)2/3
(B)5/7
(C)6/7
(D)4/49
(E)6/49
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6 comments:
e
E
(2/7) * (3/7) = 6 / 49
e
E
(2/7)*(3/7)=6/49 E is the correct answer
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