If 720 is the product of the consecutive integers
beginning with 2 and ending with n, what is the
value of n-1?
(A) 5
(B) 6
(C) 8
(D) 11
(E) 23
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11 comments:
a
can u explain me the answer
can u explain me the answer
can u explain me the answer
can u explain me the answer
its easy rakesh
consequetive integers are denoted as
1 2 3 4 5 6 7.....n
since the beginning integer is 2
and the product is given as 720
therefore n-1 would be 5
since 2*3=6
6*4=24
24*5= 120
120*6=720
so n is 6 therefore n-1 implies (6-1)
=5
A
ya a is the correct answer and logically time saving answer is given
720 according to condition as now see the products of it 360,240etc but
according to condition 2 is the starting and n is ending so consider240 k and now n=0as per the 240 we have now add 2+4+0=6 k now by condition n-1 so 6-1=5.
k its logic answer max it works in all these type of questions k
tat was grea
a
but we have to consider consecutive numbers...
i think ans is c
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