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Sunday, February 4, 2007

"MATH PROBLEM OF THE DAY"

A father is three times as old as his son. After fifteen years the father will be twice as old as his son's age at that time. Hence the father's present age is

36
42
45
48
None of the above

14 comments:

Unknown said...: Ans: C; February 4, 2007 at 8:44 PM
Unknown said...: explain..plss; February 4, 2007 at 9:09 PM
Pinu13 said...: F=3S and 15 yrs from now F+15=2(S+15), now substitute and solve...u will get S=15 ,hence F=45; February 4, 2007 at 9:49 PM
sona said...: c; February 4, 2007 at 10:35 PM
Unknown said...: F=3x,S=x.after 15 years..F=3x+15,S=x+15
3x+15=2(x+15).solving...S=15;F3*15=45..
hence C; February 5, 2007 at 12:29 AM
Unknown said...: answer is C; February 5, 2007 at 12:38 AM
Poongundran said...: c; February 5, 2007 at 7:14 AM
Admin said...: CORRECT ANS IS C 45
SO SALIMA,AND TARU THANX FOR CORRECT EXPLAINATION; February 5, 2007 at 12:03 PM
Anonymous said...: c; February 6, 2007 at 12:26 AM
Unknown said...: c; February 6, 2007 at 8:42 AM
Unknown said...: C; February 6, 2007 at 11:50 AM
DIFFICULTY IS ROUTINE.... I DO THE IMPOSSIBLE said...: C; February 8, 2007 at 7:52 PM
Unknown said...: C; February 10, 2007 at 7:21 AM
Anonymous said...: answer is 45; February 11, 2007 at 5:45 PM

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