Thursday, February 8, 2007

"ALGEBRA QUESTION OF THE DAY"

For what values of 'm' is y = 0, if y = x2 + (2m + 1)x + m2 - 1? x is a real number.

(1) m -2
(2) m < 0
(3) m = 0
(4) m -1.25
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4 comments:

Anonymous said...

i think it cannot b possible bcoz there is a term x2 which does not have any coeff in terms of m

February 10, 2007 at 6:58 AM
Anonymous said...

the answer is m=0

February 10, 2007 at 10:43 AM
Anonymous said...

i think the answer is m<0

February 11, 2007 at 5:25 PM
kanhaiya kumar said...

For what values of 'm' is y = 0, if y = x2 + (2m + 1)x + m2 - 1? x is a real number.

since,this is a objective question so,need not to solve in detail
for m<0 arbitraly a small value is chosen so,that max. term become 0.let,m=-1'
then,eqn.will be y=x2-x=x(x-1)=0 or 1 i.e y=0
there are more method for this if interested contact me.

hence, righat ans. is m<0

February 12, 2007 at 3:34 AM

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