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Thursday, April 9, 2009

GRE QUESTION ON DEMAND

BD=8
AB=6
ED=5
EF=FC
AF=?
OPTIONS:
A)4.5
B)3
C)4
D)3.5
E)5

sent by: KRITI AGARWAL

10 comments:

Unknown said...: EF cannot be equal to FC.. think it is EF=EC..
since we know EC=3-->(1/2(AB))&ED=5
implies CD=4
BC=AF=4
ans c; April 9, 2009 at 10:26 PM
Anonymous said...: c; April 10, 2009 at 11:42 PM
Anonymous said...: C I.E 4
TOO EASY; April 13, 2009 at 12:03 AM
priya said...: C; April 16, 2009 at 1:30 PM
Ravisekharan (a) Ravi said...: But ABCF is not mentioned to be a RECTANGLE at all??; May 30, 2009 at 2:03 PM
Saikrishnaraju said...: ya here ef cany be equal 2 fc..so if we take it as fe=ec tn he ans zz c(4); June 10, 2009 at 8:22 AM
Anonymous said...: this is a flawed question bc it i don't see how one can just assume right angels; August 11, 2009 at 6:25 PM
sampath said...: wats dat bc should bc shld be same as cd; September 20, 2009 at 11:09 AM
Anonymous said...: c, assuming 90 degree angles are drawn as 90 degrees; November 5, 2009 at 4:31 PM
Mayank said...: It's C; February 8, 2010 at 7:02 AM