One alloy of metal contains 90%copper & 10%tin. Another alloy contains 95%copper &5%tin. If they are mixed so that the mixture contains 9%tin then what % of copper will it contain?
A)90
B)65
C)85
D)75
E)80
correct answer:75
should'nt it be 100-9=91%?
please explain!!
Sent by: KRITI AGARWAL
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18 comments:
correct ans 75
it s 91% rite??
how come 75??
how cum 75??? giv it solution....
logically it shud b 91 only..
it is 91....mathematically it cums out 91 too... logically also... 75 is wrong for sure..
ok...correct answer is 75 but i also think it is 91%...maybe prinitng error then..thanks guys nonetheless:)
ok...correct answer is 75 but i also think it is 91%...maybe prinitng error then..thanks guys nonetheless:)
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Ans is 75 :
Solution:
(90)(10) + (95)(5) = (x)(9)
x=153
153 is 75% of 200 ( As we are mixing 2 Alloys i.e (100 +100 )
pls explain the soln.
dere is no logic behind ur solution....its wrong
plz explain clearly
wat the heck...ur solution is amazingly wrong..u r multiplying Cu and Tin %ages..and equating..absolutly wrong..ans is 91%..bcoz thr is no impurity in either alloys(simple logic)..
ur genius with ur innosence?????????is it 75????really
if we go with the answer it said
Cu=75%
Sn=9%
total=84%
where is the rest 16%...
can anybody explain....as it is mentioned that it contain 2 metals...
75
Answer is 91 % for sure even den
suppose x : 1 is the proportion in which we mixed it den
(10 * x + 5)/(x + 1) = 9
=> x = 4/1
=> first mixture : second mixture :: 4 : 1
=> (90 * 4 + 95 * 1)/( 4 + 1) = 91
so 91 % is correct answer..
it´s 65%!
plz explain it
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