Wednesday, February 28, 2007

"MATH PROBLEM OF THE DAY"

7 identical balls have to be distributed to 4 people such that each one gets at least one ball. What are the number of ways of distribution such that at least one gets 3 balls?

A) 7
B) 28
C) 81
D) 2401
E) None of these

3 comments:

goyalakshay said...

E

Anonymous said...

how ??
exp

Unknown said...

i'll xplain u how.....
first ....
1out of 4 gets 3 balls...
so d left over 4 balls r distributed among 3ppl...dis can b done in (1,1,2) or (1,2,1) or(2,1,1)..... so dis comes 2 three ways..... no if v change d guy who has 3 balls... again u hav three ways....so.on... it goes for 4 ppl.. therefore.... (3*4)=12 ways....
dis can also b done in simple way...... it is (4!/2!) which is = 12