A gardener wishes to plant 5 bushes in a straight row.
Each bush has flowers of a different solid color
(white, yellow, pink red, and purple). How many
ways can the bushes be arranged so that the middle bush is the one with red flowers?
(A) 24
(B) 30
(C) 60
(D) 96
(E) 120
BY-- SHRUTHI from BANGALORE
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13 comments:
4! = 24.... _ _RED_ _.IN how many ways can u arrange 4 different things in 4 different ways....?? 4!
24 a
24 is the ans... since middle one is fixed we can arrange other 4 in 4! factorial ways
i guess it is 120 coz there are 5 bushes
4*3*2*1=24
d ?... 4!* 4!* 4!* 4!= 96 .
ans is A
i am a bit confuse now.....
is the combination
Pink Purple Red Yellow White
equal to
White Yellow Red Purple Pink
i guess when you say Red is in the middle then relative to Red these combinations are equal.
so it should be 24 / 2 == 12 :P :P
it's 4*3*1*2*1=24
ans is 4c2 * 2! bcoz
In given 5 places red is for middle and the first two places can be arranged with 4 flowers in 4c2 ways and the remaining last tow places with remaining two flowers in 2! ways therefore ans is 12 ways
ans is 24
a
a 24 is correct 4!=24 also one thing is possible 4!*4!*4!*4!*4!=120
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