If 2.5pi * 10^5 cubic feet of earth are to be removed
in constructing a tunnel in the shape of a right
circular cylinder 20 feet in diameter, what will be
the length, in feet, of the tunnel?
(A) 25,000
(B) 12,500
(C) 5,000
(D) 2,500
(E) 1,250
Subscribe to:
Post Comments (Atom)
Posts
5 comments:
2500 feet.....
e - 1250 feet
vol is given as 2.5*3.14*10^5
ie 2.5*3.14*50
now cylinder d= 20 , r=10 , h=h;
3.14*100*h = 2.5*3.14*50
h=1250 feet
2500 feet....
vol is given as 2.5*3.14*10^5
ie 2.5*3.14*50
now cylinder d= 20 , r=10 , h=h;
3.14*100*h = 2.5*3.14*(10^5)
h=2500 feet
vol is given as 2.5*3.14*10^5
ie 2.5*3.14*50
now cylinder d= 20 , r=10 , h=h;
3.14*100*h = 2.5*3.14*(10^5)
h=2500 feet
ans A..................
Post a Comment