Friday, May 18, 2007

MATH PROBLEM OF THE DAY

Speed bumps are being placed at 20 foot intervals along a road 1015 feet long. If the first
speed bump is placed at one end of the road, how many speed bumps are needed?
(A) 49 (B) 50 (C) 51 (D) 52 (E) 53

13 comments:

Anonymous said...

D

shubhamshrestha said...

c i believe

Unknown said...

i feel it is A

Anonymous said...

c is the answer,
1015/20=50.7
so approx 51.

Unknown said...

C

Anonymous said...

C... 50.75 approx....51

Anonymous said...

the correct answer is ....D

Vinay said...

1015/20 = 50.75, approximate to 51! So C is the answer.

Aditya`s take said...

there s no approximation required...its 51 as there is one initially at the begining of the road..then its 50 speed bumps along the road...for eg...at 0 m there s one.then at 20 there s another(totally 2)and at 40 one more (totally 3) and so on..so totally this way 51 bumps are required...there s no approximation involved in the problem

Unknown said...

i belive the ans is 50 becoz in the case of speed bumps u need one for every 20m so for a total of 1015 u need 1015/20=50 and u wl place another one at 1020 but hav only 1015 so u dont need any othr speed bump so the ans is 50

Unknown said...

u cant use approximations in this case tht concept doesnt apply here

Anonymous said...

1st @ 0 ,
2nd @ 20 ...,
5th @ 80.....
10th @ 180....,
50th @ 980....,
51st @ 1000 thats it....
no more speed bumps....

Anonymous said...

i think by calculation C is the correct answer