If x and y are prime numbers such that x > y > 2, then x^2 − y^2 must be divisible by which one of the
following numbers?
(A) 3
(B) 4
(C) 5
(D) 9
(E) 12
Friday, May 18, 2007
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8 comments:
B
b
B
explain
for ex...5>3>2...thn B is correct
Bt if 4>3>2...thn...16-9=7 !!!
thn wats the ans here....?
can some1 explain?
the question says prime no.
so we take 2 prime nos..
for eg 5 and 3.....5*5-3*3=16 divisible by 4
aand if we take 7*7-3*3 =40 its again divisible by 4.....so the answer is ...b
Let X and Y be the primes......
since both X & Y are !=2
X & Y are both odd numbers...
trivial evens can't be primes....
so let X = 2m+1
Y = 2n+1
=> X^2 - Y^2 = (X+Y) (X-Y)
= (2m+2n+2)(2m-2n)
= 4 (m+n+1)(m-n)
so definitely divisible by 4 :)
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