Wednesday, April 11, 2007

"MATH PROBLEM OF THE DAY'

The ages of three people are such that the age of one person is twice the age of the second person and
three times the age of the third person. If the sum of the ages of the three people is 33, then the age of
the youngest person is
(A) 3
(B) 6
(C) 9
(D) 11
(E) 18
at

3 comments:

  1. AnonymousApril 11, 2007 at 12:58 PM

    let X,Y&Z be the ages of the three person resply
    according to the question
    X=2Y=3Z
    further
    X+Y+Z=33
    =>2Y+Y+2y/3=33
    =>11Y=99
    Y=9
    therefore X=18
    and Z=6
    answer is B

    ReplyDelete
  2. MadhurApril 11, 2007 at 6:35 PM

    why cant I solve like this
    x+2x+3x= 33
    6x = 33

    ???
    plz help ...

    ReplyDelete
  3. AnonymousApril 11, 2007 at 9:04 PM

    by taking X you cant exactly define the second and third person presicely..ask yourself...then you will understand

    ReplyDelete