Wednesday, April 11, 2007

"ALGEBRA QUESTION OF THE DAY"

Let a, b, and c be three integers, and let a be a perfect square. If a/b = b/c, then which one of the
following statements must be true?
(A) c must be an even number
(B) c must be an odd number
(C) c must be a perfect square
(D) c must not be a perfect square
(E) c must be a prime number
at

4 comments:

  1. AnonymousApril 11, 2007 at 1:01 PM

    d

    ReplyDelete
  2. MadhurApril 11, 2007 at 6:30 PM

    any reason ?
    what if
    b=3
    c=9
    then a = 81

    ReplyDelete
  3. NikhilApril 12, 2007 at 9:12 PM

    d

    a/b=b/c

    hence c=b^2/a

    now chose ne perfect sq value of a say 4 and chose ne value for b say 3 it gives c as 9/4

    c cannot be a pure no. as c is mostly a fraction

    i think its 'D'

    ReplyDelete
  4. AnonymousApril 15, 2007 at 2:30 AM

    c is a square number. reason:
    let a=k^2
    since a/b=b/c
    ac=b^2
    hence (k^2)*c=b^2
    or c=(b/k)^2
    hence c is a perfect square

    ReplyDelete