A train of length l, traveling at a constant velocity, passes a pole in t seconds. If the same train
traveling at the same velocity passes a platform in 3t seconds, then the length of the platform is
(A) 0.5l
(B) l
(C) 1.5l
(D) 2l
(E) 3l
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9 comments:
e
its D yaar...
explanation~>
vt=l...(1)
3vt=(l+p)
so,2vt=p
so,2*t*l/t=p
so,2l=p
ya itz d guy
sorry itz not d itz "e"
the velocity = l/t
the time taken to cross the platform = 3t
therefore the length of the platform = l/t x 3t
= 3l
hence e is correct
sorry ..
d is correct
because the length of the train is to be taken into consideration
3l is (l+y)
y is the distance of the platform
so y = (3l-l)
= 2l
3l ans is (e)
ans is (d) 2l
(D) IS ANSWER
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