Wednesday, January 31, 2007

"MATH PROBLEM OF THE DAY"

Column A
Number of ways in which 5 differently coloured beads be strung on a necklace.
Column B
5!/2
A) if the quantity in column A is greater.
B) if the quantity in column B is greater.
C) if the quantities are equal.
D) if the relationship cannot be determined from the information given.

6 comments:

Poongundran said...
This comment has been removed by the author.
Pinu13 said...

a

Anonymous said...

Answer is A.

Suma said...

a
5!>5!/2

Ankit said...

a

Anonymous said...

B is the answer...
since necklace is round...according to circular permutations concept....the number of ways of arranging 'n' different things is (n-1)!....so the answer is (5-1)!=4!=24
therefore,24<5!/2
ie.24<60
hence the correct answer is B.