In △ABC, AB =6, BC = 8, and CA =10.5
COLUMN A--The measure of angle ABC
COLUMN B--90º
Thursday, June 21, 2007
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19 comments:
angle is not 90...6*6 + 8*8 not eq 10.5 * 10.5 ....and how ever u add u cant get rt angled triplet coz 6 and 8 are integers but 10.5 is not...
ya angle is not 90...so..column A is greater...cos if it were 6.4 the 3rd side shud ve been 10...so it has to be greater than 90...cos sides opposite to greater angles are gr8er...guess am rite??
i mean if the sides are 6 and 8...the third side wil be 10 for a rite angled triangle...since its 10.5 the angle is gr8er than 90 which implies column A is gr8er...
*sorry my prev comment was a bit obscure...*
column A is greater...
since 9.somethin is the hypotenuse of a right angled traingle with sides 6 and 8...we see that 10 is something which is more than that hence the angle needs to be more than 90 degress in order to accomodate the third side..so coloumn A is larger
column b is greater
a is greater
column a is greater
A IS GREATER
a is greater
A
A is correct
a
since 6^2 + 8^2 < 10.5^2
column a is greater
i am sure d ans is A
>90 deg,if right triangle hypotenuse would be 10,side as 10.5 = >90
ANS is A..........
let angle of b be 90 then sum of squares of sides must be equal to hyop 6^2+8^2=100 then hypo is 10....... so my point is the given length is greater than 10 so angle will be greater than 90
A
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B .......... C
For a righta anfled TRIANGLE
AB=6;BC=8;AC=10...
IF AC increases the angle ABC increases and the Triangle Becomes obtuse.
The general condition for this Question can be stated as
Obtuse... AC^2 > AB^2+BC^2
Right...AC^2 = AB^2+BC^2
Acute....AC^2 < AB^2+BC^2
column A is greater then B
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