The ages of three people are such that the age of one person is twice the age of the second person and
three times the age of the third person. If the sum of the ages of the three people is 33, then the age of
the youngest person is
(A) 3
(B) 6
(C) 9
(D) 11
(E) 18
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7 comments:
b
X+Y+Z=33
X=2Y 3Z=2Y
X=3Z
2Y+Y+2Y/3=33
=>6Y+3Y+2Y/3 =33
=>11Y=99
=>Y=9(COFFEE)
THEREFORE X=18(THUMBS UP)
AND Z=6(SMALL BOY...DRINK MAAZA)
GUNDASWAMI FROM VELLORE
B
B
Let a represent the age of the oldest person, b the age of the age of second person, and c the age of
youngest person. The age of first person is twice the age of the second person and three times the age of the
third person. This can be expressed as a = 2b and a = 3c. Solving these equations for b and c yields b = a/2
and c = a/3. The sum of the ages of the three people is a + b + c = 33. Substituting for b and c in this
equation, we get
a + a/2 + a/3 = 33
6a + 3a + 2a = 198 by multiplying both sides by 6
11a = 198
a = 198/11 = 18 by dividing both sides by 11
Since c = a/3, we get
c = a/3 = 18/3 = 6
The answer is (B).
B
B IS THE CORRECT ANSWER
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