Let a, b, and c be three integers, and let a be a perfect square. If a/b = b/c, then which one of the
following statements must be true?
(A) c must be an even number
(B) c must be an odd number
(C) c must be a perfect square
(D) c must not be a perfect square
(E) c must be a prime number
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4 comments:
d
any reason ?
what if
b=3
c=9
then a = 81
d
a/b=b/c
hence c=b^2/a
now chose ne perfect sq value of a say 4 and chose ne value for b say 3 it gives c as 9/4
c cannot be a pure no. as c is mostly a fraction
i think its 'D'
c is a square number. reason:
let a=k^2
since a/b=b/c
ac=b^2
hence (k^2)*c=b^2
or c=(b/k)^2
hence c is a perfect square
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