Steve bought some apples at a cost of $.60 each and some oranges at a cost of $.50 each. If he paid a
total of $4.10 for a total of 8 apples and oranges, how many apples did Steve buy?
(A) 1
(B) 2
(C) 3
(D) 5
(E) 6
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If X denotes the number of apples
& Y denotes the number of oranges
then X+Y=8(total number of apples and oranges)
since cost of each apple is $0.60 &
oranges is 0.50$
and the total cost is $4.10
0.60X + 0.50Y =4.10
=>.6X + .5(8-X)=4.10
=>.6x +4 - .5X =4.10
=> 0.1X= 0.1
=>X=1
numbers of apple is only 1
number of oranges is 7
1.
1
1
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