Monday, February 12, 2007

"ALGEBRA QUESTION OF THE DAY"

What is the greatest value of a positive integer n such that 3n is a factor of 1815?
  1. 15
  2. 18
  3. 30
  4. 33
  5. 45
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4 comments:

Anonymous said...

well the answer is 33

February 12, 2007 at 10:00 PM
Anonymous said...

if ans is 33 then 3n == 99 shld divide 1815....
there is some flaw in the question....
1815 = 3 * 5 * 11 * 11
so 3n == 5,11,121,55 or 605

February 13, 2007 at 4:53 AM
diya said...

whats the correct answer
is it 33

February 13, 2007 at 9:24 AM
Anonymous said...

wrngque

March 1, 2007 at 12:29 AM

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