Tuesday, January 30, 2007

'GRE ALGEBRA QUESTION OF THE DAY"

The number of numbers that can be formed by the digits 1,2,3,4,3,2,1. the odd digits are at odd places is given by

A) 430
B) 215
C) 93
D) 36
E) 18

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5 comments:

Pinu13 said...

E

January 30, 2007 at 5:38 AM
Unknown said...

y?????????
can u explation
i think question is missing
must given the no of digit numbr we hav 2 form
like 3-digit r 4- digit r 7- digit
not findind 2 solving clue

January 30, 2007 at 8:19 AM
Pinu13 said...

Well..as far as my understanding of the Question goes..we rae suppossed to make 7 digits numbers from the ones given ..keeping the odd numbers (1,3) at the odd places ...theresfore there are 6 arrangements possible for the odd nuumbers..i.e 1331,1133,3311,3113,1313,3131 and in between them there are 3 possible arrangments of 2,4,2 amongst each of the arrangements of odd numbers..therefore 18

January 30, 2007 at 8:38 AM
Unknown said...

nice attempt.....dude
u may b correct

January 30, 2007 at 2:56 PM
Admin said...

ya salimA u r absolutely correct
correct ans is E.
CORRECT EXPLANATION.

February 1, 2007 at 10:51 AM

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