Thursday, January 18, 2007

"GRE ALGEBRA QUESTION OF THE DAY"

If ((t^2)-1)/(t-1)=2, then what value(s) may t have?
A) 1 only
B) -1 only
C) 1 or -1
D) no values
E) an infimite number of values
Posted by at

5 comments:

ankur said...

a

January 18, 2007 at 9:59 AM
Unknown said...

A

January 19, 2007 at 5:25 AM
Samip Shah said...

It can't be A , bcoz if t=1 then denomenator becomes 0 and hence answer does not comply with RHS

It has to be No values i guess

January 19, 2007 at 7:09 AM
Anonymous said...

no value is the answer....cor the munerator b'comes 0 even if t is + or -1

January 20, 2007 at 3:49 AM
Unknown said...

+1 or -1
it will be (t^2-1)=2(t-1), hence (t^2-1)-2(t-1)=0 so taking t-1 common v get (t-1)[t+1-2]=0 which has 2 solutions t=1 or t=-1

November 11, 2007 at 11:07 AM

Post a Comment

Subscribe to: Post Comments (Atom)