Saturday, August 18, 2007

GRE MATH PROBLEM OF THE DAY

What percent of the integers between 100 and 999,
inclusive, have all three digits the same?
(A) 1%
(B) 2%
(C) 3%
(D) 4%
(E) 5%

22 comments:

  1. there r nine numbers ex. 111,222,........999
    total no. from 100 to 999 are 900
    then percentage is
    (9\900)*100
    =1%

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  2. they r totaly 8 number r there in between 100 to 999...that is 111 222 333 444 555 666 777 888 and 999 is not include ... so (8\888)*100 = 0.98 therefore it is 1%

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  3. They are 8 numbers (111 - 888) and their percent from 899 numbers is 0.89% which is approximately 1% so the closest answer is A.

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  4. First we have to find the how many numbers b/w 100 to 999 inclusiv.
    mean total numbers b/w a to b inclusive is b-a+1.
    that is total numbers are 900
    the numbers have same digits are
    111,222,333,444,555,666,777,888,999
    Totally 9 are ther

    Percentage=9/900*100=1%

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  5. 1% as there is one three digit no. with the same no. for every hundred nos. and so there are totally 900 nos. between 100 and 999 therefore the percentage can be calculated as follows:
    [9/900]*100=1%

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  6. my answer is 1% because out of 900 numbers there are only 9 numbers having allthree same digits ie 9/900=1%

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  7. hey de answer is 1% but it shud b 8/898 but not 8/888 as mentioned by [b]kirankumar3561[/b]cos v hav 999-100-1 numbers b'ween 100-999

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  8. YES by calculation A 1% is correct answer

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