Monday, July 2, 2007

GRE QUESTION ON DEMAND

A gardener wishes to plant 5 bushes in a straight row.
Each bush has flowers of a different solid color
(white, yellow, pink red, and purple). How many
ways can the bushes be arranged so that the middle bush is the one with red flowers?
(A) 24
(B) 30
(C) 60
(D) 96
(E) 120

BY-- SHRUTHI from BANGALORE
at

13 comments:

  1. Sid AryanJuly 3, 2007 at 12:10 AM

    4! = 24.... _ _RED_ _.IN how many ways can u arrange 4 different things in 4 different ways....?? 4!

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  2. DeepakJuly 3, 2007 at 5:39 AM

    24 a

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  3. UnknownJuly 6, 2007 at 11:51 AM

    24 is the ans... since middle one is fixed we can arrange other 4 in 4! factorial ways

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  4. AnonymousJuly 7, 2007 at 10:12 PM

    i guess it is 120 coz there are 5 bushes

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  5. UnknownJuly 8, 2007 at 10:57 AM

    4*3*2*1=24

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  6. AnonymousJuly 10, 2007 at 7:25 AM

    d ?... 4!* 4!* 4!* 4!= 96 .

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  7. sidhuJuly 15, 2007 at 12:42 AM

    ans is A

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  8. AnonymousJuly 16, 2007 at 11:28 PM

    i am a bit confuse now.....
    is the combination
    Pink Purple Red Yellow White
    equal to
    White Yellow Red Purple Pink
    i guess when you say Red is in the middle then relative to Red these combinations are equal.
    so it should be 24 / 2 == 12 :P :P

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  9. AnonymousJuly 17, 2007 at 5:07 AM

    it's 4*3*1*2*1=24

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  10. Sai GuruvaAugust 2, 2007 at 8:25 AM

    ans is 4c2 * 2! bcoz
    In given 5 places red is for middle and the first two places can be arranged with 4 flowers in 4c2 ways and the remaining last tow places with remaining two flowers in 2! ways therefore ans is 12 ways

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  11. AnonymousAugust 2, 2007 at 11:56 PM

    ans is 24

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  12. HappyBloggerAugust 3, 2007 at 5:54 AM

    a

    ReplyDelete
  13. AnonymousSeptember 4, 2008 at 2:59 AM

    a 24 is correct 4!=24 also one thing is possible 4!*4!*4!*4!*4!=120

    ReplyDelete