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ya angle is not 90...so..column A is greater...cos if it were 6.4 the 3rd side shud ve been 10...so it has to be greater than 90...cos sides opposite to greater angles are gr8er...guess am rite??
i mean if the sides are 6 and 8...the third side wil be 10 for a rite angled triangle...since its 10.5 the angle is gr8er than 90 which implies column A is gr8er...
since 9.somethin is the hypotenuse of a right angled traingle with sides 6 and 8...we see that 10 is something which is more than that hence the angle needs to be more than 90 degress in order to accomodate the third side..so coloumn A is larger
let angle of b be 90 then sum of squares of sides must be equal to hyop 6^2+8^2=100 then hypo is 10....... so my point is the given length is greater than 10 so angle will be greater than 90
angle is not 90...6*6 + 8*8 not eq 10.5 * 10.5 ....and how ever u add u cant get rt angled triplet coz 6 and 8 are integers but 10.5 is not...
ReplyDeleteya angle is not 90...so..column A is greater...cos if it were 6.4 the 3rd side shud ve been 10...so it has to be greater than 90...cos sides opposite to greater angles are gr8er...guess am rite??
ReplyDeletei mean if the sides are 6 and 8...the third side wil be 10 for a rite angled triangle...since its 10.5 the angle is gr8er than 90 which implies column A is gr8er...
ReplyDelete*sorry my prev comment was a bit obscure...*
column A is greater...
ReplyDeletesince 9.somethin is the hypotenuse of a right angled traingle with sides 6 and 8...we see that 10 is something which is more than that hence the angle needs to be more than 90 degress in order to accomodate the third side..so coloumn A is larger
ReplyDeletecolumn b is greater
ReplyDeletea is greater
ReplyDeletecolumn a is greater
ReplyDeleteA IS GREATER
ReplyDeletea is greater
ReplyDeleteA
ReplyDeleteA is correct
ReplyDeletea
ReplyDeletesince 6^2 + 8^2 < 10.5^2
column a is greater
i am sure d ans is A
ReplyDelete>90 deg,if right triangle hypotenuse would be 10,side as 10.5 = >90
ReplyDeleteANS is A..........
ReplyDeletelet angle of b be 90 then sum of squares of sides must be equal to hyop 6^2+8^2=100 then hypo is 10....... so my point is the given length is greater than 10 so angle will be greater than 90
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ReplyDeleteA
ReplyDelete.
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B .......... C
For a righta anfled TRIANGLE
AB=6;BC=8;AC=10...
IF AC increases the angle ABC increases and the Triangle Becomes obtuse.
The general condition for this Question can be stated as
Obtuse... AC^2 > AB^2+BC^2
Right...AC^2 = AB^2+BC^2
Acute....AC^2 < AB^2+BC^2
column A is greater then B
ReplyDelete