Thursday, June 21, 2007

GRE ALGEBRA QUESTION OF THE DAY

Which of the following CANNOT be a factor of 2^i and
3^j , where i and j are positive integers?
(A) 6
(B) 8
(C) 27
(D) 42
(E) 54

16 comments:

Anonymous said...

it can be either 8 or 27 coz,it was given as both multiple pf 2 "AND" 3

Anonymous said...

it can be 42 because , 42 is not only (purly) multiple of 2^i and 3^j ie
42=2*3*7 ... 7 is not a multiple of 2^i and 3^j.

Anonymous said...

27

Anonymous said...

i think its 8.
8 is not a factor of 3

Avinash Reddy said...

my answer is 8
bcos 8 is a factor of 2 but not 3

Anonymous said...

if its 8 bcoz its not factor of 3 then 27 not factor of 2 ? how can u give that xplanation?

Anonymous said...

I think its 42 ,as all others the factors are 2 and 3 and only 42 has a 7 in it .

Sriram.R said...

its 42 . cos the possible factors are powers of 2 or powers of 3 or multiples of 6 and 42 doesn km under any of the above.

Aditya`s take said...
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Aditya`s take said...
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Anonymous said...

The Answer will b 42
Bcause only in that along with 2 and 3 there is a no. 7 which is not allowed according 2 the statement
42=2*3*7

Anonymous said...

42 ,because ,
42= 2*3*7

7 is not in choice

Aditya`s take said...

actually the question is wrong...

i and j are positive integers...

hence for 8 and 27

8=2^3*3^0

27 = 3^3 * 2^0


HENCE THE QUESTION IS WRONG

Unknown said...

d . since 2*3*7=42 not possible

Unknown said...

yah even i think the both 8 and 27 are the ans, cos 3 is not a factor of 8 and 2 is not a factor to 27.

The Q says to find out the no. that isnt a multiple of both 2&3. In other words we have to find the no. that is not a multiple of 6.

Hence the ans are both 8 and 27 according to me.

Anonymous said...

i think it is 42 bcoz,
2^3 = 8, 3^3 = 27, 2^1*3^1 = 6,
2^1*3^3 = 54 but, 2^1*3^1*7^1 = 42