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Friday, June 15, 2007
GRE ALGEBRA QUESTION OF THE DAY
If 720 is the product of the consecutive integers beginning with 2 and ending with n, what is the value of n-1? (A) 5 (B) 6 (C) 8 (D) 11 (E) 23
ya a is the correct answer and logically time saving answer is given 720 according to condition as now see the products of it 360,240etc but according to condition 2 is the starting and n is ending so consider240 k and now n=0as per the 240 we have now add 2+4+0=6 k now by condition n-1 so 6-1=5. k its logic answer max it works in all these type of questions k
a
ReplyDeletecan u explain me the answer
ReplyDeletecan u explain me the answer
ReplyDeletecan u explain me the answer
ReplyDeletecan u explain me the answer
ReplyDeleteits easy rakesh
ReplyDeleteconsequetive integers are denoted as
1 2 3 4 5 6 7.....n
since the beginning integer is 2
and the product is given as 720
therefore n-1 would be 5
since 2*3=6
6*4=24
24*5= 120
120*6=720
so n is 6 therefore n-1 implies (6-1)
=5
A
ReplyDeleteya a is the correct answer and logically time saving answer is given
ReplyDelete720 according to condition as now see the products of it 360,240etc but
according to condition 2 is the starting and n is ending so consider240 k and now n=0as per the 240 we have now add 2+4+0=6 k now by condition n-1 so 6-1=5.
k its logic answer max it works in all these type of questions k
tat was grea
ReplyDeletea
ReplyDeletebut we have to consider consecutive numbers...
ReplyDeletei think ans is c