Friday, May 18, 2007

MATH PROBLEM OF THE DAY

Speed bumps are being placed at 20 foot intervals along a road 1015 feet long. If the first
speed bump is placed at one end of the road, how many speed bumps are needed?
(A) 49 (B) 50 (C) 51 (D) 52 (E) 53
at

13 comments:

  1. AnonymousMay 18, 2007 at 1:17 PM

    D

    ReplyDelete
  2. shubhamshresthaMay 20, 2007 at 10:18 AM

    c i believe

    ReplyDelete
  3. UnknownMay 21, 2007 at 1:31 AM

    i feel it is A

    ReplyDelete
  4. AnonymousMay 21, 2007 at 7:02 AM

    c is the answer,
    1015/20=50.7
    so approx 51.

    ReplyDelete
  5. UnknownMay 21, 2007 at 10:30 PM

    C

    ReplyDelete
  6. AnonymousMay 22, 2007 at 10:28 AM

    C... 50.75 approx....51

    ReplyDelete
  7. AnonymousMay 23, 2007 at 5:19 AM

    the correct answer is ....D

    ReplyDelete
  8. VinayMay 23, 2007 at 7:52 AM

    1015/20 = 50.75, approximate to 51! So C is the answer.

    ReplyDelete
  9. Aditya`s takeMay 23, 2007 at 11:32 PM

    there s no approximation required...its 51 as there is one initially at the begining of the road..then its 50 speed bumps along the road...for eg...at 0 m there s one.then at 20 there s another(totally 2)and at 40 one more (totally 3) and so on..so totally this way 51 bumps are required...there s no approximation involved in the problem

    ReplyDelete
  10. UnknownJune 1, 2007 at 5:24 AM

    i belive the ans is 50 becoz in the case of speed bumps u need one for every 20m so for a total of 1015 u need 1015/20=50 and u wl place another one at 1020 but hav only 1015 so u dont need any othr speed bump so the ans is 50

    ReplyDelete
  11. UnknownJune 1, 2007 at 5:25 AM

    u cant use approximations in this case tht concept doesnt apply here

    ReplyDelete
  12. AnonymousJune 4, 2007 at 2:17 AM

    1st @ 0 ,
    2nd @ 20 ...,
    5th @ 80.....
    10th @ 180....,
    50th @ 980....,
    51st @ 1000 thats it....
    no more speed bumps....

    ReplyDelete
  13. AnonymousSeptember 7, 2008 at 2:32 AM

    i think by calculation C is the correct answer

    ReplyDelete