Sunday, April 29, 2007

MATH PROBLEM OF THE DAY

The age of B is half the sum of the ages of A and C. If B is 2 years younger than A and C is 32 years
old, then the age of B must be
(A) 28
(B) 30
(C) 32
(D) 34
(E) 36

6 comments:

Unknown said...

B

Anonymous said...

D

Madhur said...

B

Bindu said...

d

Nags said...

D.

a+c = 2b
a-2 = b (-)
________
c+2= b (c=32)
so b = 32+2 = 34

Admin said...

Let a represent the age of A and let c represent the age of C. If b represents the age of B, then
according to the question b = [a + c]/2
. We are told that B is 2 years younger than A. This generates the
equation a = b + 2. We know that the age of C is 32. Substituting these values into the equation b =
[a + c]/2
yields b =
[(b + 2) + 32]/2
. Solving this equation for b yields b = 34. The answer is (D).