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Sunday, April 1, 2007
"MATH PROBLEM OF THE DAY"
A train of length l, traveling at a constant velocity, passes a pole in t seconds. If the same train traveling at the same velocity passes a platform in 3t seconds, then the length of the platform is (A) 0.5l (B) l (C) 1.5l (D) 2l (E) 3l
sorry .. d is correct because the length of the train is to be taken into consideration 3l is (l+y) y is the distance of the platform so y = (3l-l) = 2l
e
ReplyDeleteits D yaar...
ReplyDeleteexplanation~>
vt=l...(1)
3vt=(l+p)
so,2vt=p
so,2*t*l/t=p
so,2l=p
ya itz d guy
ReplyDeletesorry itz not d itz "e"
ReplyDeletethe velocity = l/t
ReplyDeletethe time taken to cross the platform = 3t
therefore the length of the platform = l/t x 3t
= 3l
hence e is correct
sorry ..
ReplyDeleted is correct
because the length of the train is to be taken into consideration
3l is (l+y)
y is the distance of the platform
so y = (3l-l)
= 2l
3l ans is (e)
ReplyDeleteans is (d) 2l
ReplyDelete(D) IS ANSWER
ReplyDelete