Saturday, March 17, 2007

"MATH PROBLEM OF THE DAY"

Steve bought some apples at a cost of $.60 each and some oranges at a cost of $.50 each. If he paid a
total of $4.10 for a total of 8 apples and oranges, how many apples did Steve buy?
(A) 1
(B) 2
(C) 3
(D) 5
(E) 6
at

5 comments:

  1. AnonymousMarch 17, 2007 at 6:31 PM

    1

    ReplyDelete
  2. AnonymousMarch 18, 2007 at 6:02 AM

    If X denotes the number of apples
    & Y denotes the number of oranges
    then X+Y=8(total number of apples and oranges)
    since cost of each apple is $0.60 &
    oranges is 0.50$
    and the total cost is $4.10

    0.60X + 0.50Y =4.10
    =>.6X + .5(8-X)=4.10
    =>.6x +4 - .5X =4.10
    => 0.1X= 0.1
    =>X=1
    numbers of apple is only 1
    number of oranges is 7

    ReplyDelete
  3. Aditya ShuklaMarch 19, 2007 at 6:47 AM

    1.

    ReplyDelete
  4. UnknownMarch 19, 2007 at 11:51 AM

    1

    ReplyDelete
  5. Dr Kranthi RajMarch 21, 2007 at 2:16 PM

    1

    ReplyDelete