Sunday, February 4, 2007

"GEOMETRY QUESTION OF THE DAY'

A plot of land is in the shape of a trapezium whose dimensions are given in the figure below :

Hence the perimeter of the field is
  1. 50 m
  2. 64 m
  3. 72 m
  4. 84 m
  5. None of the above

14 comments:

sona said...

[(5*12)/2 ]+ [(9*12)/2] + [(16*12)/2]= 180

so the answer is non of them!

Pinu13 said...

How can the perimeter be 180 when already the sum of 3 sides given is 52..the fourth side cannot be 128????!
answer is 72..cuz BC=20

Unknown said...

answer is c

Unknown said...

answer is none of the above

Anonymous said...

answer is c as sum of three sides is 52 & the fourth side is 20

Admin said...

YA CORRECT ANS IS C 72
SALIMA IS ABSOLUTELY CORRECT
ALSO CONGRATS RADHA, FOR CORRECT ANS

Vinay said...

k

Anonymous said...

E
the right hand side is forming a right triangle, so that 4th side will be 13m & then the perimeter comes out 2 b 65, so the answer is none of the above

Anonymous said...

The answer is 72...Another side of the diagonal is 20 units...So adding all we get 72...

Unknown said...

how that diagonal value is 20.i think it is wrong.the ans is none of the above.

DIFFICULTY IS ROUTINE.... I DO THE IMPOSSIBLE said...

C

Unknown said...

C

Anonymous said...

its 64 i think

Anonymous said...

answer: C
draw a perpendicular from point A onto seg DC..let the point on seg DC be F...triangle ADF is a right angled triangle and is a 13-12-5 traingle(AF=BE=12)..so DF=5,FE=AB=9 and DC=30...so EC=16...now,BEC is another right angled triangle...now find out BC as BE=12 and EC=16...BC=20...perimeter is equal to 9+20+30+13=72...hope this clears everybody's doubts...