Wednesday, January 31, 2007

"MATH PROBLEM OF THE DAY"

Column A
Number of ways in which 5 differently coloured beads be strung on a necklace.
Column B
5!/2
A) if the quantity in column A is greater.
B) if the quantity in column B is greater.
C) if the quantities are equal.
D) if the relationship cannot be determined from the information given.
at

6 comments:

  1. PoongundranJanuary 31, 2007 at 8:08 AM

    This comment has been removed by the author.

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  2. Pinu13January 31, 2007 at 8:15 AM

    a

    ReplyDelete
  3. AnonymousJanuary 31, 2007 at 11:51 AM

    Answer is A.

    ReplyDelete
  4. SumaJanuary 31, 2007 at 8:44 PM

    a
    5!>5!/2

    ReplyDelete
  5. AnkitFebruary 1, 2007 at 2:07 AM

    a

    ReplyDelete
  6. AnonymousJune 24, 2007 at 6:23 AM

    B is the answer...
    since necklace is round...according to circular permutations concept....the number of ways of arranging 'n' different things is (n-1)!....so the answer is (5-1)!=4!=24
    therefore,24<5!/2
    ie.24<60
    hence the correct answer is B.

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