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The number of defects in the first five cars to come through a new production line are 9, 7, 10, 4, and 6, respectively. If the sixth car through the production line has either 3, 7, or 12 defects, for which of theses values does the mean number of defects per car for the first six cars equal the median?
I. 3
II. 7
III. 12
A. I only
B. II only
C. III only
D. I and III only
E. I, II, and III
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6 comments:
a
i think its option D
for the first case ie no 3..
median 6.5 and mean 6.5
for the second no. ie 12
median = 8
mean = 8
hence option d
confirm the answer pls
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possilble sequence is
3 4 6 7 9 10
4 6 7 7 9 10
4 6 7 9 10 12
median can be 6.5 7 8
b
possilble sequence is
3 4 6 7 9 10
4 6 7 7 9 10
4 6 7 9 10 12
median can be 6.5 7 8
it is D
Answer: D
in case the sixth defect is 3,mean will be 39/9=6.5 and 3 4 6 7 9 10,so median will be 6+7=13/2=6.5
in case the sixth defect is 7,mean will be 43/6 > 7 and median will be 7( 4 6 7 7 9 10 )
in case the sixth defect is 12, mean will be 48/6=8 and median will be 8
( 4 6 7 9 10 12)...
so only 3 and 12 values give mean= median...only 1 and 3 are correct...answer is D
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