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Monday, January 15, 2007
"GRE MATH PROBLEM OF THE DAY"
A man is known to speak truth 3 out of 4 times. He throws die and reports that it is a 6. The probability that it is actually a 6 is A) 3/4 B) 5/8 C) 2/5 D) 3/5 E) 4/5
its A.
ReplyDeleteprobability P1=3/4 he is saying a truth.
p2=1/2 its a 6
probability p3=1/4 hr is lying
p4=1/2 its not a 6
P=(P1*P2)/(P1*P2+P3*P4) using Bayes Theorem