Monday, January 15, 2007

"GRE MATH PROBLEM OF THE DAY"

A man is known to speak truth 3 out of 4 times. He throws die and reports that it is a 6. The probability that it is actually a 6 is
A) 3/4
B) 5/8
C) 2/5
D) 3/5
E) 4/5

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1 comment:

Unknown said...

its A.

probability P1=3/4 he is saying a truth.
p2=1/2 its a 6

probability p3=1/4 hr is lying

p4=1/2 its not a 6

P=(P1*P2)/(P1*P2+P3*P4) using Bayes Theorem

November 11, 2007 at 11:35 AM

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