Friday, April 10, 2009

GRE QUESTION ON DEMAND

200 gms of a solution was10% sugar by weight. 500gms were replaced by a second solution resulting in a solution that was 16% sugar by weight. The second solution is what percent sugar by weight?
A)34%
B)24%
C)22%
D)18%
E)8.5%

sent by: KRITI AGARWAL
at

11 comments:

  1. rohitApril 11, 2009 at 1:15 AM

    34%

    ReplyDelete
  2. AnonymousApril 18, 2009 at 11:16 PM

    pls explain

    ReplyDelete
  3. UnknownApril 28, 2009 at 7:50 PM

    22%

    ReplyDelete
  4. Aevum DicessioMay 24, 2009 at 10:49 AM

    can anyone explain the question?? 500gms of wat am nt getting... the solution is originally 200gms rite??

    ReplyDelete
  5. AnonymousAugust 11, 2009 at 6:08 PM

    The answer is 18%
    2/7 (.1) + 5/7 (X) = .16

    then solve

    ReplyDelete
  6. AnonymousAugust 26, 2009 at 12:45 PM

    why divide 2 and 5 by 7

    ReplyDelete
  7. AnonymousOctober 27, 2009 at 5:37 AM

    ((2/2+5)*(.1))+((5/2+5)*X)=.16

    Which gives the solution as 18%

    ReplyDelete
  8. AnonymousJuly 11, 2010 at 2:51 AM

    Its 22 - c)

    Its a solution so consider the solution to contain 1000gms of which sugar is 10%.

    Now we are taking 500gms out of it and mixing it up with x% sugar solution so that the total sugar% is 16%.

    y% req to bring 10% to 16& = 16 - 10 = 6
    x% = 16 + y = 22 %

    ReplyDelete
  9. AnonymousDecember 23, 2010 at 10:52 AM

    d)18
    original sum(% difference in weaker solution and new solution)=new sum(% difference new solution and weaker solution)

    200(16-10)=500(x-16)
    1200=500x-9200
    x=18.4% or 18%

    ReplyDelete
  10. AnonymousJanuary 16, 2011 at 1:37 PM

    which one is correct, c) or d)

    ReplyDelete
  11. SurekhadeviMay 27, 2011 at 1:06 PM

    Question is not '200', but '2000'.

    Solution is below
    (2000-500)*0.1 + 500*x = 2000*0.16
    x = 0.34

    So answer is 34%

    ReplyDelete