Thursday, April 9, 2009

GRE QUESTION ON DEMAND





BD=8
AB=6
ED=5
EF=FC
AF=?
OPTIONS:
A)4.5
B)3
C)4
D)3.5
E)5

sent by: KRITI AGARWAL
at

10 comments:

  1. UnknownApril 9, 2009 at 10:26 PM

    EF cannot be equal to FC.. think it is EF=EC..
    since we know EC=3-->(1/2(AB))&ED=5
    implies CD=4
    BC=AF=4
    ans c

    ReplyDelete
  2. AnonymousApril 10, 2009 at 11:42 PM

    c

    ReplyDelete
  3. AnonymousApril 13, 2009 at 12:03 AM

    C I.E 4
    TOO EASY

    ReplyDelete
  4. priyaApril 16, 2009 at 1:30 PM

    C

    ReplyDelete
  5. Ravisekharan (a) RaviMay 30, 2009 at 2:03 PM

    But ABCF is not mentioned to be a RECTANGLE at all??

    ReplyDelete
  6. SaikrishnarajuJune 10, 2009 at 8:22 AM

    ya here ef cany be equal 2 fc..so if we take it as fe=ec tn he ans zz c(4)

    ReplyDelete
  7. AnonymousAugust 11, 2009 at 6:25 PM

    this is a flawed question bc it i don't see how one can just assume right angels

    ReplyDelete
  8. sampathSeptember 20, 2009 at 11:09 AM

    wats dat bc should bc shld be same as cd

    ReplyDelete
  9. AnonymousNovember 5, 2009 at 4:31 PM

    c, assuming 90 degree angles are drawn as 90 degrees

    ReplyDelete
  10. MayankFebruary 8, 2010 at 7:02 AM

    It's C

    ReplyDelete