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Monday, July 2, 2007
GRE GEOMETRY QUESTION OF THE DAY
If 2.5pi * 10^5 cubic feet of earth are to be removed in constructing a tunnel in the shape of a right circular cylinder 20 feet in diameter, what will be the length, in feet, of the tunnel? (A) 25,000 (B) 12,500 (C) 5,000 (D) 2,500 (E) 1,250
2500 feet.....
ReplyDeletee - 1250 feet
ReplyDeletevol is given as 2.5*3.14*10^5
ie 2.5*3.14*50
now cylinder d= 20 , r=10 , h=h;
3.14*100*h = 2.5*3.14*50
h=1250 feet
2500 feet....
ReplyDeletevol is given as 2.5*3.14*10^5
ie 2.5*3.14*50
now cylinder d= 20 , r=10 , h=h;
3.14*100*h = 2.5*3.14*(10^5)
h=2500 feet
vol is given as 2.5*3.14*10^5
ReplyDeleteie 2.5*3.14*50
now cylinder d= 20 , r=10 , h=h;
3.14*100*h = 2.5*3.14*(10^5)
h=2500 feet
ans A..................
ReplyDelete