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Sunday, April 29, 2007
MATH PROBLEM OF THE DAY
The age of B is half the sum of the ages of A and C. If B is 2 years younger than A and C is 32 years old, then the age of B must be (A) 28 (B) 30 (C) 32 (D) 34 (E) 36
Let a represent the age of A and let c represent the age of C. If b represents the age of B, then according to the question b = [a + c]/2 . We are told that B is 2 years younger than A. This generates the equation a = b + 2. We know that the age of C is 32. Substituting these values into the equation b = [a + c]/2 yields b = [(b + 2) + 32]/2 . Solving this equation for b yields b = 34. The answer is (D).
B
ReplyDeleteD
ReplyDeleteB
ReplyDeleted
ReplyDeleteD.
ReplyDeletea+c = 2b
a-2 = b (-)
________
c+2= b (c=32)
so b = 32+2 = 34
Let a represent the age of A and let c represent the age of C. If b represents the age of B, then
ReplyDeleteaccording to the question b = [a + c]/2
. We are told that B is 2 years younger than A. This generates the
equation a = b + 2. We know that the age of C is 32. Substituting these values into the equation b =
[a + c]/2
yields b =
[(b + 2) + 32]/2
. Solving this equation for b yields b = 34. The answer is (D).