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Thursday, February 8, 2007
"MATH PROBLEM OF THE DAY"
A man can hit a target once in 4 shots. If he fires 4 shots in succession, what is the probability that he will hit his target?
therefore prob of not hiting the target =(1-1/4)=3/4.
now,4 cases r possible:- case.1>he shoots the aim in the first attempt. case.2>he misses the aim in the first attempt but hits it in the second attempt. case.3>he misses the aim in the first and second attempt but hits the target in the third attempt. case.4>he misses the aim in the first second & third attempt but hits the target in the fourth one. hence, prob of hitting the target=((1/4)+(3/4*1/4)+(3/4*3/4*1/4)+(3/4*3/4*3/4*1/4)) =>175/216.ans
1
ReplyDelete2
ReplyDelete1
ReplyDeleteit should be 1
ReplyDeleteit should be 1
ReplyDeleteit should be 1
ReplyDeletecan u explain me the answer
ReplyDeleteit is 1/256
ReplyDeleteit is 1/256
ReplyDeleteprobabity of hiting the target =1/4.
ReplyDeletetherefore prob of not hiting the target =(1-1/4)=3/4.
now,4 cases r possible:-
case.1>he shoots the aim in the first attempt.
case.2>he misses the aim in the first attempt but hits it in the second attempt.
case.3>he misses the aim in the first and second attempt but hits the target in the third attempt.
case.4>he misses the aim in the first second & third attempt but hits the target in the fourth one.
hence,
prob of hitting the target=((1/4)+(3/4*1/4)+(3/4*3/4*1/4)+(3/4*3/4*3/4*1/4))
=>175/216.ans