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Monday, February 5, 2007
"MATH PROBLEM OF THE DAY"
At 10 a.m. two trains started traveling toward each other from stations 287 miles apart. They passed each other at 1:30 p.m. the same day. If the average speed of the faster train exceeded the average speed of the slower train by 6 miles per hour, which of the following represents the speed of the faster train, in miles per hour?
D=S*T
ReplyDelete287=(x+x+6)*7/2
x=38
x+6=44
ans is c
44 mph...
ReplyDeleteC
ReplyDeleteC
ReplyDeletec
ReplyDeleteits 44
ReplyDelete