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Sunday, February 4, 2007
"MATH PROBLEM OF THE DAY"
A father is three times as old as his son. After fifteen years the father will be twice as old as his son's age at that time. Hence the father's present age is
Ans: C
ReplyDeleteexplain..plss
ReplyDeleteF=3S and 15 yrs from now F+15=2(S+15), now substitute and solve...u will get S=15 ,hence F=45
ReplyDeletec
ReplyDeleteF=3x,S=x.after 15 years..F=3x+15,S=x+15
ReplyDelete3x+15=2(x+15).solving...S=15;F3*15=45..
hence C
answer is C
ReplyDeletec
ReplyDeleteCORRECT ANS IS C 45
ReplyDeleteSO SALIMA,AND TARU THANX FOR CORRECT EXPLAINATION
c
ReplyDeletec
ReplyDeleteC
ReplyDeleteC
ReplyDeleteC
ReplyDeleteanswer is 45
ReplyDelete