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Sunday, February 4, 2007
"GEOMETRY QUESTION OF THE DAY'
A plot of land is in the shape of a trapezium whose dimensions are given in the figure below : Hence the perimeter of the field is
E the right hand side is forming a right triangle, so that 4th side will be 13m & then the perimeter comes out 2 b 65, so the answer is none of the above
answer: C draw a perpendicular from point A onto seg DC..let the point on seg DC be F...triangle ADF is a right angled triangle and is a 13-12-5 traingle(AF=BE=12)..so DF=5,FE=AB=9 and DC=30...so EC=16...now,BEC is another right angled triangle...now find out BC as BE=12 and EC=16...BC=20...perimeter is equal to 9+20+30+13=72...hope this clears everybody's doubts...
[(5*12)/2 ]+ [(9*12)/2] + [(16*12)/2]= 180
ReplyDeleteso the answer is non of them!
How can the perimeter be 180 when already the sum of 3 sides given is 52..the fourth side cannot be 128????!
ReplyDeleteanswer is 72..cuz BC=20
answer is c
ReplyDeleteanswer is none of the above
ReplyDeleteanswer is c as sum of three sides is 52 & the fourth side is 20
ReplyDeleteYA CORRECT ANS IS C 72
ReplyDeleteSALIMA IS ABSOLUTELY CORRECT
ALSO CONGRATS RADHA, FOR CORRECT ANS
k
ReplyDeleteE
ReplyDeletethe right hand side is forming a right triangle, so that 4th side will be 13m & then the perimeter comes out 2 b 65, so the answer is none of the above
The answer is 72...Another side of the diagonal is 20 units...So adding all we get 72...
ReplyDeletehow that diagonal value is 20.i think it is wrong.the ans is none of the above.
ReplyDeleteC
ReplyDeleteC
ReplyDeleteits 64 i think
ReplyDeleteanswer: C
ReplyDeletedraw a perpendicular from point A onto seg DC..let the point on seg DC be F...triangle ADF is a right angled triangle and is a 13-12-5 traingle(AF=BE=12)..so DF=5,FE=AB=9 and DC=30...so EC=16...now,BEC is another right angled triangle...now find out BC as BE=12 and EC=16...BC=20...perimeter is equal to 9+20+30+13=72...hope this clears everybody's doubts...