Thursday, February 1, 2007

"ALGEBRA QUESTION OF THE DAY"

If x is the product of the positive integers from 1 to 8, inclusive, and if i, k, m, and p are positive integers such that x = 2i3k5m7p, then i + k + m + p =

A) 4
B) 7
C) 8
D) 11
E) 12

at

9 comments:

  1. AnonymousFebruary 1, 2007 at 6:13 PM

    I think answer is 19 (1+4+6+8). Can't think of any other way to solve for one of the answers given.

    ReplyDelete
  2. Pinu13February 1, 2007 at 10:59 PM

    i too am getting 19

    ReplyDelete
  3. UnknownFebruary 2, 2007 at 3:52 AM

    19.

    ReplyDelete
  4. shanmuFebruary 2, 2007 at 7:43 AM

    ya 19..

    ReplyDelete
  5. UnknownFebruary 2, 2007 at 8:04 AM

    ya its 19

    ReplyDelete
  6. sonaFebruary 2, 2007 at 8:53 AM

    i don't think these answeres be correct!
    if x = 2i3k5m7p,
    than we have:
    x=2,?, 3,4,5,6,7,8
    so what should be i? i can not be 1 casue we write all in oeder and if we are allowed to use them in inorder we be no sure about otheres!

    then i + k + m + p = ?

    ReplyDelete
  7. AnkitFebruary 3, 2007 at 3:32 AM

    This comment has been removed by the author.

    ReplyDelete
  8. AnonymousFebruary 3, 2007 at 3:33 AM

    admin ??

    ReplyDelete
  9. Maya VishwakarmaFebruary 3, 2007 at 8:23 AM

    yaar wts correct ans...??

    ReplyDelete